The City of Alexander had a population of 193 as of July 1, 2018. Alexander ranks in the lower quartile for Population Density and the upper quartile for Diversity Index when compared to the other cities, towns and Census Designated Places (CDPs) in Iowa. See peer rankings below.
The primary coordinate point for Alexander is located at latitude 42.8044 and longitude -93.4786 in Franklin County. The formal boundaries for the City of Alexander (see map below) encompass a land area of 4.27 sq. miles and a water area of 0 sq. miles. Franklin County is in the Central time zone (GMT -6). The elevation is 1,270 feet.
The City of Alexander (GNIS ID: 2393915) has a C1 Census Class Code which indicates an active incorporated place that does not serve as a county subdivision equivalent. It also has a Functional Status Code of "A" which identifies an active government providing primary general-purpose functions.
|Population in Households||193|
|Population in Familes||156|
|Population in Group Qrtrs||0|
|Median Household Income||$58,395|
|Average Household Income||$85,058|
|Per Capita Income||$35,112|
|Total Housing Units||89 (100%)|
|Owner Occupied HU||63 (70.8%)|
|Renter Occupied HU||14 (15.7%)|
|Vacant Housing Units||12 (13.5%)|
|Median Home Value||$109,375|
|Average Home Value||$137,500|
|Average Household Size||2.51|
|Average Family Size||3|
GROWTH RATE / YEAR
|Median Household Income||3.41%|
|Per Capita Income||2.8%|
The table below compares Alexander to the other 1,009 incorporated cities, towns and CDPs in Iowa by rank and percentile using July 1, 2018 data. The location Ranked # 1 has the highest value. A location that ranks higher than 75% of its peers would be in the 75th percentile of the peer group.
|Total Population||# 706||30th|
|Population Density||# 997||1st|
|Diversity Index||# 136||87th|
|Median Household Income||# 377||63rd|
|Per Capita Income||# 137||87th|
Additional comparisons and rankings can be made with a VERY EASY TO USE Iowa Census Data Comparison Tool.